3.6.92 \(\int \frac {(a+b x^3)^{2/3}}{x^7 (a d-b d x^3)} \, dx\) [592]

Optimal. Leaf size=284 \[ -\frac {5 b \left (a+b x^3\right )^{2/3}}{18 a^2 d x^3}-\frac {\left (a+b x^3\right )^{5/3}}{6 a^2 d x^6}+\frac {14 b^2 \tan ^{-1}\left (\frac {\sqrt [3]{a}+2 \sqrt [3]{a+b x^3}}{\sqrt {3} \sqrt [3]{a}}\right )}{9 \sqrt {3} a^{7/3} d}-\frac {2^{2/3} b^2 \tan ^{-1}\left (\frac {\sqrt [3]{a}+2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} a^{7/3} d}-\frac {7 b^2 \log (x)}{9 a^{7/3} d}+\frac {b^2 \log \left (a-b x^3\right )}{3 \sqrt [3]{2} a^{7/3} d}+\frac {7 b^2 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{9 a^{7/3} d}-\frac {b^2 \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} a^{7/3} d} \]

[Out]

-5/18*b*(b*x^3+a)^(2/3)/a^2/d/x^3-1/6*(b*x^3+a)^(5/3)/a^2/d/x^6-7/9*b^2*ln(x)/a^(7/3)/d+1/6*b^2*ln(-b*x^3+a)*2
^(2/3)/a^(7/3)/d+7/9*b^2*ln(a^(1/3)-(b*x^3+a)^(1/3))/a^(7/3)/d-1/2*b^2*ln(2^(1/3)*a^(1/3)-(b*x^3+a)^(1/3))*2^(
2/3)/a^(7/3)/d+14/27*b^2*arctan(1/3*(a^(1/3)+2*(b*x^3+a)^(1/3))/a^(1/3)*3^(1/2))/a^(7/3)/d*3^(1/2)-1/3*2^(2/3)
*b^2*arctan(1/3*(a^(1/3)+2^(2/3)*(b*x^3+a)^(1/3))/a^(1/3)*3^(1/2))/a^(7/3)/d*3^(1/2)

________________________________________________________________________________________

Rubi [A]
time = 0.19, antiderivative size = 284, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 8, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {457, 105, 154, 162, 57, 631, 210, 31} \begin {gather*} \frac {14 b^2 \text {ArcTan}\left (\frac {2 \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt {3} \sqrt [3]{a}}\right )}{9 \sqrt {3} a^{7/3} d}-\frac {2^{2/3} b^2 \text {ArcTan}\left (\frac {2^{2/3} \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} a^{7/3} d}+\frac {b^2 \log \left (a-b x^3\right )}{3 \sqrt [3]{2} a^{7/3} d}+\frac {7 b^2 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{9 a^{7/3} d}-\frac {b^2 \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} a^{7/3} d}-\frac {7 b^2 \log (x)}{9 a^{7/3} d}-\frac {5 b \left (a+b x^3\right )^{2/3}}{18 a^2 d x^3}-\frac {\left (a+b x^3\right )^{5/3}}{6 a^2 d x^6} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x^3)^(2/3)/(x^7*(a*d - b*d*x^3)),x]

[Out]

(-5*b*(a + b*x^3)^(2/3))/(18*a^2*d*x^3) - (a + b*x^3)^(5/3)/(6*a^2*d*x^6) + (14*b^2*ArcTan[(a^(1/3) + 2*(a + b
*x^3)^(1/3))/(Sqrt[3]*a^(1/3))])/(9*Sqrt[3]*a^(7/3)*d) - (2^(2/3)*b^2*ArcTan[(a^(1/3) + 2^(2/3)*(a + b*x^3)^(1
/3))/(Sqrt[3]*a^(1/3))])/(Sqrt[3]*a^(7/3)*d) - (7*b^2*Log[x])/(9*a^(7/3)*d) + (b^2*Log[a - b*x^3])/(3*2^(1/3)*
a^(7/3)*d) + (7*b^2*Log[a^(1/3) - (a + b*x^3)^(1/3)])/(9*a^(7/3)*d) - (b^2*Log[2^(1/3)*a^(1/3) - (a + b*x^3)^(
1/3)])/(2^(1/3)*a^(7/3)*d)

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 57

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(1/3)), x_Symbol] :> With[{q = Rt[(b*c - a*d)/b, 3]}, Simp[-L
og[RemoveContent[a + b*x, x]]/(2*b*q), x] + (Dist[3/(2*b), Subst[Int[1/(q^2 + q*x + x^2), x], x, (c + d*x)^(1/
3)], x] - Dist[3/(2*b*q), Subst[Int[1/(q - x), x], x, (c + d*x)^(1/3)], x])] /; FreeQ[{a, b, c, d}, x] && PosQ
[(b*c - a*d)/b]

Rule 105

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[b*(a +
b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + Dist[1/((m + 1)*(b*
c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*(m + 1) - b*(d*e*(m + n + 2) +
c*f*(m + p + 2)) - b*d*f*(m + n + p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && ILtQ[m, -1] &
& (IntegerQ[n] || IntegersQ[2*n, 2*p] || ILtQ[m + n + p + 3, 0])

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && ILtQ[m, -1] && GtQ[n, 0]

Rule 162

Int[(((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :>
Dist[(b*g - a*h)/(b*c - a*d), Int[(e + f*x)^p/(a + b*x), x], x] - Dist[(d*g - c*h)/(b*c - a*d), Int[(e + f*x)
^p/(c + d*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x]

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 457

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] &&
NeQ[b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]

Rule 631

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[a*(c/b^2)]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int \frac {\left (a+b x^3\right )^{2/3}}{x^7 \left (a d-b d x^3\right )} \, dx &=\frac {1}{3} \text {Subst}\left (\int \frac {(a+b x)^{2/3}}{x^3 (a d-b d x)} \, dx,x,x^3\right )\\ &=-\frac {\left (a+b x^3\right )^{5/3}}{6 a^2 d x^6}-\frac {\text {Subst}\left (\int \frac {(a+b x)^{2/3} \left (-\frac {5}{3} a b d-\frac {1}{3} b^2 d x\right )}{x^2 (a d-b d x)} \, dx,x,x^3\right )}{6 a^2 d}\\ &=-\frac {5 b \left (a+b x^3\right )^{2/3}}{18 a^2 d x^3}-\frac {\left (a+b x^3\right )^{5/3}}{6 a^2 d x^6}-\frac {\text {Subst}\left (\int \frac {-\frac {28}{9} a^2 b^2 d^2-\frac {8}{9} a b^3 d^2 x}{x \sqrt [3]{a+b x} (a d-b d x)} \, dx,x,x^3\right )}{6 a^3 d^2}\\ &=-\frac {5 b \left (a+b x^3\right )^{2/3}}{18 a^2 d x^3}-\frac {\left (a+b x^3\right )^{5/3}}{6 a^2 d x^6}+\frac {\left (2 b^3\right ) \text {Subst}\left (\int \frac {1}{\sqrt [3]{a+b x} (a d-b d x)} \, dx,x,x^3\right )}{3 a^2}+\frac {\left (14 b^2\right ) \text {Subst}\left (\int \frac {1}{x \sqrt [3]{a+b x}} \, dx,x,x^3\right )}{27 a^2 d}\\ &=-\frac {5 b \left (a+b x^3\right )^{2/3}}{18 a^2 d x^3}-\frac {\left (a+b x^3\right )^{5/3}}{6 a^2 d x^6}-\frac {7 b^2 \log (x)}{9 a^{7/3} d}+\frac {b^2 \log \left (a-b x^3\right )}{3 \sqrt [3]{2} a^{7/3} d}-\frac {\left (7 b^2\right ) \text {Subst}\left (\int \frac {1}{\sqrt [3]{a}-x} \, dx,x,\sqrt [3]{a+b x^3}\right )}{9 a^{7/3} d}+\frac {b^2 \text {Subst}\left (\int \frac {1}{\sqrt [3]{2} \sqrt [3]{a}-x} \, dx,x,\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} a^{7/3} d}+\frac {\left (7 b^2\right ) \text {Subst}\left (\int \frac {1}{a^{2/3}+\sqrt [3]{a} x+x^2} \, dx,x,\sqrt [3]{a+b x^3}\right )}{9 a^2 d}-\frac {b^2 \text {Subst}\left (\int \frac {1}{2^{2/3} a^{2/3}+\sqrt [3]{2} \sqrt [3]{a} x+x^2} \, dx,x,\sqrt [3]{a+b x^3}\right )}{a^2 d}\\ &=-\frac {5 b \left (a+b x^3\right )^{2/3}}{18 a^2 d x^3}-\frac {\left (a+b x^3\right )^{5/3}}{6 a^2 d x^6}-\frac {7 b^2 \log (x)}{9 a^{7/3} d}+\frac {b^2 \log \left (a-b x^3\right )}{3 \sqrt [3]{2} a^{7/3} d}+\frac {7 b^2 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{9 a^{7/3} d}-\frac {b^2 \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} a^{7/3} d}-\frac {\left (14 b^2\right ) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+\frac {2 \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}\right )}{9 a^{7/3} d}+\frac {\left (2^{2/3} b^2\right ) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+\frac {2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}\right )}{a^{7/3} d}\\ &=-\frac {5 b \left (a+b x^3\right )^{2/3}}{18 a^2 d x^3}-\frac {\left (a+b x^3\right )^{5/3}}{6 a^2 d x^6}+\frac {14 b^2 \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{9 \sqrt {3} a^{7/3} d}-\frac {2^{2/3} b^2 \tan ^{-1}\left (\frac {1+\frac {2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{\sqrt {3} a^{7/3} d}-\frac {7 b^2 \log (x)}{9 a^{7/3} d}+\frac {b^2 \log \left (a-b x^3\right )}{3 \sqrt [3]{2} a^{7/3} d}+\frac {7 b^2 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{9 a^{7/3} d}-\frac {b^2 \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} a^{7/3} d}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]
time = 0.52, size = 316, normalized size = 1.11 \begin {gather*} \frac {-9 a^{4/3} \left (a+b x^3\right )^{2/3}-24 \sqrt [3]{a} b x^3 \left (a+b x^3\right )^{2/3}+28 \sqrt {3} b^2 x^6 \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}}{\sqrt {3}}\right )-18\ 2^{2/3} \sqrt {3} b^2 x^6 \tan ^{-1}\left (\frac {1+\frac {2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}}{\sqrt {3}}\right )+28 b^2 x^6 \log \left (-\sqrt [3]{a}+\sqrt [3]{a+b x^3}\right )-18\ 2^{2/3} b^2 x^6 \log \left (-2 \sqrt [3]{a}+2^{2/3} \sqrt [3]{a+b x^3}\right )-14 b^2 x^6 \log \left (a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^3}+\left (a+b x^3\right )^{2/3}\right )+9\ 2^{2/3} b^2 x^6 \log \left (2 a^{2/3}+2^{2/3} \sqrt [3]{a} \sqrt [3]{a+b x^3}+\sqrt [3]{2} \left (a+b x^3\right )^{2/3}\right )}{54 a^{7/3} d x^6} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x^3)^(2/3)/(x^7*(a*d - b*d*x^3)),x]

[Out]

(-9*a^(4/3)*(a + b*x^3)^(2/3) - 24*a^(1/3)*b*x^3*(a + b*x^3)^(2/3) + 28*Sqrt[3]*b^2*x^6*ArcTan[(1 + (2*(a + b*
x^3)^(1/3))/a^(1/3))/Sqrt[3]] - 18*2^(2/3)*Sqrt[3]*b^2*x^6*ArcTan[(1 + (2^(2/3)*(a + b*x^3)^(1/3))/a^(1/3))/Sq
rt[3]] + 28*b^2*x^6*Log[-a^(1/3) + (a + b*x^3)^(1/3)] - 18*2^(2/3)*b^2*x^6*Log[-2*a^(1/3) + 2^(2/3)*(a + b*x^3
)^(1/3)] - 14*b^2*x^6*Log[a^(2/3) + a^(1/3)*(a + b*x^3)^(1/3) + (a + b*x^3)^(2/3)] + 9*2^(2/3)*b^2*x^6*Log[2*a
^(2/3) + 2^(2/3)*a^(1/3)*(a + b*x^3)^(1/3) + 2^(1/3)*(a + b*x^3)^(2/3)])/(54*a^(7/3)*d*x^6)

________________________________________________________________________________________

Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {\left (b \,x^{3}+a \right )^{\frac {2}{3}}}{x^{7} \left (-b d \,x^{3}+a d \right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^3+a)^(2/3)/x^7/(-b*d*x^3+a*d),x)

[Out]

int((b*x^3+a)^(2/3)/x^7/(-b*d*x^3+a*d),x)

________________________________________________________________________________________

Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(2/3)/x^7/(-b*d*x^3+a*d),x, algorithm="maxima")

[Out]

-integrate((b*x^3 + a)^(2/3)/((b*d*x^3 - a*d)*x^7), x)

________________________________________________________________________________________

Fricas [A]
time = 3.73, size = 660, normalized size = 2.32 \begin {gather*} \left [-\frac {18 \cdot 4^{\frac {1}{3}} \sqrt {3} a b^{2} x^{6} \left (-\frac {1}{a}\right )^{\frac {1}{3}} \arctan \left (\frac {1}{3} \cdot 4^{\frac {1}{3}} \sqrt {3} {\left (b x^{3} + a\right )}^{\frac {1}{3}} \left (-\frac {1}{a}\right )^{\frac {1}{3}} - \frac {1}{3} \, \sqrt {3}\right ) - 42 \, \sqrt {\frac {1}{3}} a b^{2} x^{6} \sqrt {-\frac {1}{a^{\frac {2}{3}}}} \log \left (\frac {2 \, b x^{3} + 3 \, \sqrt {\frac {1}{3}} {\left (2 \, {\left (b x^{3} + a\right )}^{\frac {2}{3}} a^{\frac {2}{3}} - {\left (b x^{3} + a\right )}^{\frac {1}{3}} a - a^{\frac {4}{3}}\right )} \sqrt {-\frac {1}{a^{\frac {2}{3}}}} - 3 \, {\left (b x^{3} + a\right )}^{\frac {1}{3}} a^{\frac {2}{3}} + 3 \, a}{x^{3}}\right ) + 9 \cdot 4^{\frac {1}{3}} a b^{2} x^{6} \left (-\frac {1}{a}\right )^{\frac {1}{3}} \log \left (4^{\frac {2}{3}} {\left (b x^{3} + a\right )}^{\frac {1}{3}} a \left (-\frac {1}{a}\right )^{\frac {2}{3}} - 2 \cdot 4^{\frac {1}{3}} a \left (-\frac {1}{a}\right )^{\frac {1}{3}} + 2 \, {\left (b x^{3} + a\right )}^{\frac {2}{3}}\right ) - 18 \cdot 4^{\frac {1}{3}} a b^{2} x^{6} \left (-\frac {1}{a}\right )^{\frac {1}{3}} \log \left (-4^{\frac {2}{3}} a \left (-\frac {1}{a}\right )^{\frac {2}{3}} + 2 \, {\left (b x^{3} + a\right )}^{\frac {1}{3}}\right ) + 14 \, a^{\frac {2}{3}} b^{2} x^{6} \log \left ({\left (b x^{3} + a\right )}^{\frac {2}{3}} + {\left (b x^{3} + a\right )}^{\frac {1}{3}} a^{\frac {1}{3}} + a^{\frac {2}{3}}\right ) - 28 \, a^{\frac {2}{3}} b^{2} x^{6} \log \left ({\left (b x^{3} + a\right )}^{\frac {1}{3}} - a^{\frac {1}{3}}\right ) + 3 \, {\left (8 \, a b x^{3} + 3 \, a^{2}\right )} {\left (b x^{3} + a\right )}^{\frac {2}{3}}}{54 \, a^{3} d x^{6}}, -\frac {18 \cdot 4^{\frac {1}{3}} \sqrt {3} a b^{2} x^{6} \left (-\frac {1}{a}\right )^{\frac {1}{3}} \arctan \left (\frac {1}{3} \cdot 4^{\frac {1}{3}} \sqrt {3} {\left (b x^{3} + a\right )}^{\frac {1}{3}} \left (-\frac {1}{a}\right )^{\frac {1}{3}} - \frac {1}{3} \, \sqrt {3}\right ) + 9 \cdot 4^{\frac {1}{3}} a b^{2} x^{6} \left (-\frac {1}{a}\right )^{\frac {1}{3}} \log \left (4^{\frac {2}{3}} {\left (b x^{3} + a\right )}^{\frac {1}{3}} a \left (-\frac {1}{a}\right )^{\frac {2}{3}} - 2 \cdot 4^{\frac {1}{3}} a \left (-\frac {1}{a}\right )^{\frac {1}{3}} + 2 \, {\left (b x^{3} + a\right )}^{\frac {2}{3}}\right ) - 18 \cdot 4^{\frac {1}{3}} a b^{2} x^{6} \left (-\frac {1}{a}\right )^{\frac {1}{3}} \log \left (-4^{\frac {2}{3}} a \left (-\frac {1}{a}\right )^{\frac {2}{3}} + 2 \, {\left (b x^{3} + a\right )}^{\frac {1}{3}}\right ) - 84 \, \sqrt {\frac {1}{3}} a^{\frac {2}{3}} b^{2} x^{6} \arctan \left (\frac {\sqrt {\frac {1}{3}} {\left (2 \, {\left (b x^{3} + a\right )}^{\frac {1}{3}} + a^{\frac {1}{3}}\right )}}{a^{\frac {1}{3}}}\right ) + 14 \, a^{\frac {2}{3}} b^{2} x^{6} \log \left ({\left (b x^{3} + a\right )}^{\frac {2}{3}} + {\left (b x^{3} + a\right )}^{\frac {1}{3}} a^{\frac {1}{3}} + a^{\frac {2}{3}}\right ) - 28 \, a^{\frac {2}{3}} b^{2} x^{6} \log \left ({\left (b x^{3} + a\right )}^{\frac {1}{3}} - a^{\frac {1}{3}}\right ) + 3 \, {\left (8 \, a b x^{3} + 3 \, a^{2}\right )} {\left (b x^{3} + a\right )}^{\frac {2}{3}}}{54 \, a^{3} d x^{6}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(2/3)/x^7/(-b*d*x^3+a*d),x, algorithm="fricas")

[Out]

[-1/54*(18*4^(1/3)*sqrt(3)*a*b^2*x^6*(-1/a)^(1/3)*arctan(1/3*4^(1/3)*sqrt(3)*(b*x^3 + a)^(1/3)*(-1/a)^(1/3) -
1/3*sqrt(3)) - 42*sqrt(1/3)*a*b^2*x^6*sqrt(-1/a^(2/3))*log((2*b*x^3 + 3*sqrt(1/3)*(2*(b*x^3 + a)^(2/3)*a^(2/3)
- (b*x^3 + a)^(1/3)*a - a^(4/3))*sqrt(-1/a^(2/3)) - 3*(b*x^3 + a)^(1/3)*a^(2/3) + 3*a)/x^3) + 9*4^(1/3)*a*b^2
*x^6*(-1/a)^(1/3)*log(4^(2/3)*(b*x^3 + a)^(1/3)*a*(-1/a)^(2/3) - 2*4^(1/3)*a*(-1/a)^(1/3) + 2*(b*x^3 + a)^(2/3
)) - 18*4^(1/3)*a*b^2*x^6*(-1/a)^(1/3)*log(-4^(2/3)*a*(-1/a)^(2/3) + 2*(b*x^3 + a)^(1/3)) + 14*a^(2/3)*b^2*x^6
*log((b*x^3 + a)^(2/3) + (b*x^3 + a)^(1/3)*a^(1/3) + a^(2/3)) - 28*a^(2/3)*b^2*x^6*log((b*x^3 + a)^(1/3) - a^(
1/3)) + 3*(8*a*b*x^3 + 3*a^2)*(b*x^3 + a)^(2/3))/(a^3*d*x^6), -1/54*(18*4^(1/3)*sqrt(3)*a*b^2*x^6*(-1/a)^(1/3)
*arctan(1/3*4^(1/3)*sqrt(3)*(b*x^3 + a)^(1/3)*(-1/a)^(1/3) - 1/3*sqrt(3)) + 9*4^(1/3)*a*b^2*x^6*(-1/a)^(1/3)*l
og(4^(2/3)*(b*x^3 + a)^(1/3)*a*(-1/a)^(2/3) - 2*4^(1/3)*a*(-1/a)^(1/3) + 2*(b*x^3 + a)^(2/3)) - 18*4^(1/3)*a*b
^2*x^6*(-1/a)^(1/3)*log(-4^(2/3)*a*(-1/a)^(2/3) + 2*(b*x^3 + a)^(1/3)) - 84*sqrt(1/3)*a^(2/3)*b^2*x^6*arctan(s
qrt(1/3)*(2*(b*x^3 + a)^(1/3) + a^(1/3))/a^(1/3)) + 14*a^(2/3)*b^2*x^6*log((b*x^3 + a)^(2/3) + (b*x^3 + a)^(1/
3)*a^(1/3) + a^(2/3)) - 28*a^(2/3)*b^2*x^6*log((b*x^3 + a)^(1/3) - a^(1/3)) + 3*(8*a*b*x^3 + 3*a^2)*(b*x^3 + a
)^(2/3))/(a^3*d*x^6)]

________________________________________________________________________________________

Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - \frac {\int \frac {\left (a + b x^{3}\right )^{\frac {2}{3}}}{- a x^{7} + b x^{10}}\, dx}{d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**3+a)**(2/3)/x**7/(-b*d*x**3+a*d),x)

[Out]

-Integral((a + b*x**3)**(2/3)/(-a*x**7 + b*x**10), x)/d

________________________________________________________________________________________

Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: NotImplementedError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(2/3)/x^7/(-b*d*x^3+a*d),x, algorithm="giac")

[Out]

Exception raised: NotImplementedError >> Unable to parse Giac output: Algebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a r

________________________________________________________________________________________

Mupad [B]
time = 5.45, size = 513, normalized size = 1.81 \begin {gather*} \frac {\frac {5\,b^2\,{\left (b\,x^3+a\right )}^{2/3}}{18\,a}-\frac {4\,b^2\,{\left (b\,x^3+a\right )}^{5/3}}{9\,a^2}}{d\,{\left (b\,x^3+a\right )}^2+a^2\,d-2\,a\,d\,\left (b\,x^3+a\right )}+\ln \left (2\,b^4\,{\left (b\,x^3+a\right )}^{1/3}-2\,2^{1/3}\,a^5\,d^2\,{\left (-\frac {b^6}{a^7\,d^3}\right )}^{2/3}\right )\,{\left (-\frac {4\,b^6}{27\,a^7\,d^3}\right )}^{1/3}+\frac {14\,\ln \left (b^4\,{\left (b\,x^3+a\right )}^{1/3}-a^5\,d^2\,{\left (\frac {b^6}{a^7\,d^3}\right )}^{2/3}\right )\,{\left (\frac {b^6}{a^7\,d^3}\right )}^{1/3}}{27}-\ln \left (4\,b^4\,{\left (b\,x^3+a\right )}^{1/3}+2\,2^{1/3}\,a^5\,d^2\,{\left (-\frac {b^6}{a^7\,d^3}\right )}^{2/3}-2^{1/3}\,\sqrt {3}\,a^5\,d^2\,{\left (-\frac {b^6}{a^7\,d^3}\right )}^{2/3}\,2{}\mathrm {i}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (-\frac {4\,b^6}{27\,a^7\,d^3}\right )}^{1/3}+\ln \left (4\,b^4\,{\left (b\,x^3+a\right )}^{1/3}+2\,2^{1/3}\,a^5\,d^2\,{\left (-\frac {b^6}{a^7\,d^3}\right )}^{2/3}+2^{1/3}\,\sqrt {3}\,a^5\,d^2\,{\left (-\frac {b^6}{a^7\,d^3}\right )}^{2/3}\,2{}\mathrm {i}\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (-\frac {4\,b^6}{27\,a^7\,d^3}\right )}^{1/3}-\frac {7\,\ln \left (2\,b^4\,{\left (b\,x^3+a\right )}^{1/3}+a^5\,d^2\,{\left (\frac {b^6}{a^7\,d^3}\right )}^{2/3}-\sqrt {3}\,a^5\,d^2\,{\left (\frac {b^6}{a^7\,d^3}\right )}^{2/3}\,1{}\mathrm {i}\right )\,\left (1+\sqrt {3}\,1{}\mathrm {i}\right )\,{\left (\frac {b^6}{a^7\,d^3}\right )}^{1/3}}{27}+\frac {7\,\ln \left (2\,b^4\,{\left (b\,x^3+a\right )}^{1/3}+a^5\,d^2\,{\left (\frac {b^6}{a^7\,d^3}\right )}^{2/3}+\sqrt {3}\,a^5\,d^2\,{\left (\frac {b^6}{a^7\,d^3}\right )}^{2/3}\,1{}\mathrm {i}\right )\,\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )\,{\left (\frac {b^6}{a^7\,d^3}\right )}^{1/3}}{27} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^3)^(2/3)/(x^7*(a*d - b*d*x^3)),x)

[Out]

((5*b^2*(a + b*x^3)^(2/3))/(18*a) - (4*b^2*(a + b*x^3)^(5/3))/(9*a^2))/(d*(a + b*x^3)^2 + a^2*d - 2*a*d*(a + b
*x^3)) + log(2*b^4*(a + b*x^3)^(1/3) - 2*2^(1/3)*a^5*d^2*(-b^6/(a^7*d^3))^(2/3))*(-(4*b^6)/(27*a^7*d^3))^(1/3)
+ (14*log(b^4*(a + b*x^3)^(1/3) - a^5*d^2*(b^6/(a^7*d^3))^(2/3))*(b^6/(a^7*d^3))^(1/3))/27 - log(4*b^4*(a + b
*x^3)^(1/3) + 2*2^(1/3)*a^5*d^2*(-b^6/(a^7*d^3))^(2/3) - 2^(1/3)*3^(1/2)*a^5*d^2*(-b^6/(a^7*d^3))^(2/3)*2i)*((
3^(1/2)*1i)/2 + 1/2)*(-(4*b^6)/(27*a^7*d^3))^(1/3) + log(4*b^4*(a + b*x^3)^(1/3) + 2*2^(1/3)*a^5*d^2*(-b^6/(a^
7*d^3))^(2/3) + 2^(1/3)*3^(1/2)*a^5*d^2*(-b^6/(a^7*d^3))^(2/3)*2i)*((3^(1/2)*1i)/2 - 1/2)*(-(4*b^6)/(27*a^7*d^
3))^(1/3) - (7*log(2*b^4*(a + b*x^3)^(1/3) + a^5*d^2*(b^6/(a^7*d^3))^(2/3) - 3^(1/2)*a^5*d^2*(b^6/(a^7*d^3))^(
2/3)*1i)*(3^(1/2)*1i + 1)*(b^6/(a^7*d^3))^(1/3))/27 + (7*log(2*b^4*(a + b*x^3)^(1/3) + a^5*d^2*(b^6/(a^7*d^3))
^(2/3) + 3^(1/2)*a^5*d^2*(b^6/(a^7*d^3))^(2/3)*1i)*(3^(1/2)*1i - 1)*(b^6/(a^7*d^3))^(1/3))/27

________________________________________________________________________________________